Answer:
D. 78°
Step-by-step explanation:
50°+28°= 78°
_______
Since the perimeter must not exceed 291.
Let the third side be x.
x + 87 + 64 < 291
x + 151 < 291.
x < 291 -151.
x < 140. (First)
But for a triangle there is what is called the Triangle Inequality Theorem. That given the two sides of a tringle, the third side of the triangle must greater than the positive difference between the two sides and less than the sum of the two sides.
So for this case. 87 and 64.
x > ( 87 - 64). x > 23.
x < (87 + 64) x < 151. Combine both inequalities.
23 < x < 151 (second).
Combining First and second. Both must be satisfied.
So we have a more accurate answer as:
23 < x < 140. x is greater than 23 and x is less than 140.
x could be 24, 25, 26, 27, ......, 139. cm.
I hope this helps.
Answer:
2 5/6
Step-by-step explanation:
2 2/4 + 1/3
First, you have to make the bottoms of the fraction the same, by figuring out the lowest common denominator. In this case it would be 12. 4x3 = 12. 3x4 = 12.
Multiply the top number by the same number you multiplied the bottom by.
We multiplied the 4 by 3, so we would also multiply the 2 by 3 (which would be 6).
Do the same for the second fraction. 1x4 = 4.
Now we have 2 6/12 + 4/12. We add the top numbers together and we get 10/12.
Now we have to reduce the fractions. We can do this in this situation by just dividing the top and bottom numbers by 2.
2 5/6
Answer:
8.71 x 10^3N - C
Step-by-step explanation:
Force = mass x acceleration
mass = 1.7 x 10^3 and acceleration = 4.75m/s^2
Force = 1.7 x 10^3 x 4.75 = 8075N = 8.71 x 10^3N
Answer:
20 m by 10 m
Step-by-step explanation:
let w be width and l be length , then
2(l + w) = 60 ( divide both sides by 2 )
l + w = 30 ( subtract w from both sides )
l = 30 - w → (1)
lw = 200 → (2)
Substitute l = 30 - w into (2)
w(30 - w) = 200 ← distribute parenthesis on left side
30w - w² = 200 ( subtract 200 from both sides )
30w - w² - 200 = 0 ( multiply through by - 1 )
w² - 30w + 200 = 0 ← in standard form
(w - 10)(w - 20) = 0 ← in factored form
Equate each factor to zero and solve for w
w - 10 = 0 ⇒ w = 10
w - 20 = 0 ⇒ w = 20
Substitute these values into (1)
l = 30 - 10 = 20
l = 30 - 20 = 10
dimensions of field is 20 m by 10 m
