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Alja [10]
2 years ago
12

Given:

Mathematics
1 answer:
wlad13 [49]2 years ago
3 0

Answer:

huh

Step-by-step explanation:

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What is the solution of the inequality x+5<533?
olga_2 [115]
X + 5 < 533         Subtract 5 from each side
    - 5     -5
-----------------
x < 528
4 0
3 years ago
One positive integer is 1 less than twice another. The sum of their squares is 106. Find the integers.
neonofarm [45]
They give us 2 pieces to the puzzle.  Both are positive numbers...x and y.
1.) 1 number is 1 less than twice another number. (x = 2y -1)...and
2.) the sum of their squares is 106.  (x^2 + y^2 = 106).

 substitute the value for x into the second equation.

(2y-1)^2 + y^2 = 106
(2y-1) (2y-1) + y^2 = 106  (use distributive property)
4y^2 - 2y - 2y + 1 + y^2 = 106  (subtract 106 from both sides)
4y^2 - 2y - 2y + 1 + y^2 - 106 = 106 - 106 (combine like terms)
5y^2 - 4y - 105 = 0  (factor)
(y-5) (5y-21) = 0  (set to 0)
y - 5 = 0
y = 5 

substitute the 5 into the equation for y   (x = 2(5) - 1)
           x = 9   if we square 9, we get 81.
subtracted from 106 we have 25...the square root of 25 is 5.

our answers are 5 and 9.
8 0
3 years ago
Suppose you invest $1400 at interest rate of 4.3% compounded continuously. How much will you have in the account after 7 years?
STatiana [176]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1400\\ r=rate\to 4.3\%\to \frac{4.3}{100}\dotfill &0.043\\ t=years\dotfill &7 \end{cases} \\\\\\ A=1400e^{0.043\cdot 7}\implies A=1400e^{0.301}\implies A\approx 1891.69\implies \stackrel{\textit{rounded up}}{A=1892}

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2 years ago
From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
zhenek [66]
1.3/13(if you mean jacks queens and kings)
2.1/52
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8 0
3 years ago
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Students in Mr. Clark's class are reading a book that has 180 pages.
Aleonysh [2.5K]

Answer:

Step-by-step explanation:

12 pages I think

4 0
3 years ago
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