well, since we know the endpoints for the diameter, its midpoint will be where the center of the circle is located, so

and if we get the distance between those endpoints, and take half of that, that'd be the radius of it.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{11})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-4 - (-10)]^2 + [11 - 5]^2}\implies d=\sqrt{(-4+10)^2+6^2} \\\\\\ d=\sqrt{6^2+6^2}\implies d=\sqrt{72}~\hfill \stackrel{radius=half~that}{\cfrac{\sqrt{72}}{2}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-10%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-4%7D~%2C~%5Cstackrel%7By_2%7D%7B11%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7Bdiameter%7D%7Bd%7D%3D%5Csqrt%7B%5B-4%20-%20%28-10%29%5D%5E2%20%2B%20%5B11%20-%205%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-4%2B10%29%5E2%2B6%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B6%5E2%2B6%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B72%7D~%5Chfill%20%5Cstackrel%7Bradius%3Dhalf~that%7D%7B%5Ccfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-7}{ h},\stackrel{8}{ k})\qquad \qquad radius=\stackrel{\frac{\sqrt{72}}{2}}{ r} \\\\\\\ [x-(-7)]^2~~ + ~~[y-8]^2~~ = ~~\left( \frac{\sqrt{72}}{2} \right)^2\implies (x+7)^2~~ + ~~(y-8)^2~~ = ~~18](https://tex.z-dn.net/?f=%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B-7%7D%7B%20h%7D%2C%5Cstackrel%7B8%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%5Cfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%7D%7B%20r%7D%20%5C%5C%5C%5C%5C%5C%5C%20%5Bx-%28-7%29%5D%5E2~~%20%2B%20~~%5By-8%5D%5E2~~%20%3D%20~~%5Cleft%28%20%5Cfrac%7B%5Csqrt%7B72%7D%7D%7B2%7D%20%5Cright%29%5E2%5Cimplies%20%28x%2B7%29%5E2~~%20%2B%20~~%28y-8%29%5E2~~%20%3D%20~~18)
Range is the y-values.
So the y-values are: {1,2,3,4}
Answer: 48
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Explanation:
The keyword "of" means multiply
150% converts to the decimal form 1.5; you move the decimal point two spots to the left to go from percent form to decimal form
Putting those two facts together lead to...
150% of 32 = 1.5*32 = 48
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Another approach:
x% = x/100
150% = 150/100 = 1.5
150% of 32 = 1.5*32 = 48
The last step is identical as before, but the conversion of 150% is slightly different this time.
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Yet another approach:
100% of anything is itself
So 100% of 32 is 32
The extra 50% means we take half of 32 to get 16. Then we add that onto the 32 to get 16+32 = 48
k there is your answer. be happy. UwU