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anygoal [31]
3 years ago
13

Write the point-slope form of an equation of the line through the points (-1, 4) and (-2, 2).

Mathematics
2 answers:
kozerog [31]3 years ago
5 0

Answer:

Point-slope form: y-4=2(x+1)

Slope intercept form: y=2x+6

I hope this helps!

xz_007 [3.2K]3 years ago
4 0

Answer:

y-4=2(x+1)

Step-by-step explanation:

Point-slope form is equal to

y-y_1=m(x-x_1)

where y and y1 are the known y coordinates of two points on the line, and x and x1 are the known x coordinates of two points on the line. All we need now is m, which is the slope:

4-2=m(-1-(-2))

We can simplify negative one minus negative two as positive 1.

4-2=m(1)

4 minus 2 is 2, so m times 1 is 2. That means m is 2.

Now, we have the slope, so we can convert to point-slope form using one of the two points. Let's use (-1, 4). We can plug those values in for x1 and y1:

y-4=2(x+1)

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Answer: 4 seeds will left over.

Step-by-step explanation:

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blsea [12.9K]

Answer:

{x,y} = {-2,-3}

Step-by-step explanation:

System of Linear Equations entered :

  [1]    -9x + 4y = 6

  [2]    9x + 5y = -33

Graphic Representation of the Equations :

   4y - 9x = 6        5y + 9x = -33  

Solve by Substitution :

// Solve equation [2] for the variable  y  

 

 [2]    5y = -9x - 33

 [2]    y = -9x/5 - 33/5

// Plug this in for variable  y  in equation [1]

  [1]    -9x + 4•(-9x/5-33/5) = 6

  [1]    -81x/5 = 162/5

  [1]    -81x = 162

// Solve equation [1] for the variable  x  

  [1]    81x = - 162  

  [1]    x = - 2  

// By now we know this much :

   x = -2

   y = -9x/5-33/5

// Use the  x  value to solve for  y  

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