Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
I’m pretty sure it’s the second option.
Answer:
To solve a system of linear equation graphically, it is best to write both equations in slope-intercept form first. After you put them in slope-intercept form, you should be able to graph them easily.For one solution, the two lines have to intersect at exactly one point, since both equations are satisfied at the intersection.
For no solution, the two lines have to never intersect, which means they have to be parallel lines. In other words, no solution will satisfy both equation.
F(n) of the sequence is: 2.5
2 x 2.5= 5
5 x 2.5= 12.5
Etc.
Answer: 74
Step-by-step explanation:
48+75+25/2
