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Zina [86]
3 years ago
13

C=wtc/1000 solve for w

Mathematics
2 answers:
8090 [49]3 years ago
4 0
C = wtc/1000
1000C = wtc      [multiply both sides by 1000]
w = 1000C/tc      [divide both sides by tc]
Nutka1998 [239]3 years ago
3 0
For this case we have the following equation:
 C =  \frac{wtc}{1000}
 To clear w, we must follow the following steps:
 1) The value of t multiplied by c pass to divide the other side of the equation:
 \frac{w}{1000} =  \frac{C}{tc}
 2) the value of 1000 is passed to multiply to the other side of the equation:
 w = \frac{1000C}{tc}
 Answer:
 
The cleared equation for w is:
 
w = \frac{1000C}{tc}
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Answer:

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Step-by-step explanation:

Given the points:

A = (4,-1)$, $B = (6,2)$, and $C = (-1,2)$.

The first step is to find the <u>Centroid</u> of the triangle.

Centroid, X

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Next, let P be a point (x,y)

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On Substitution into: PA^2 + PB^2 + PC^2 = 3PX^2 + k

(x-4)^2+(y-(-1))^2+(x-6)^2+(y-2)^2+(x-(-1))^2+(y-2)^2=3[(x-3)^2+(y-1)^2]+k

Let us simplify the LHS first

\\LHS: x^2-8x+16+y^2+2y+1+x^2-12x+36+y^2\\-4y+4+x^2+2x+1+y^2-4y+4\\=3x^2-18x+3y^2-6y+62

Also, the Right Hand Side

RHS:3[(x-3)^2+(y-1)^2]+k\\=3[x^2-6x+9+y^2-2y+1]+k\\=3x^2-18x+27+3y^2-6y+3+k\\=3x^2+3y^2-18x-6y+30+k

Therefore:

3x^2-18x+3y^2-6y+62=3x^2+3y^2-18x-6y+30+k\\k=3x^2-18x+3y^2-6y+62-3x^2-3y^2+18x+6y-30\\k=3x^2-3x^2+3y^2-3y^2-18x+18x+62-30\\k=32

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