Considering that we have the standard deviation for the sample, the t-distribution will be used, and the critical value is t = 2.6682.
<h3>When should the t-distribution and the z-distribution be used?</h3>
- If we have the standard deviation for the sample, the t-distribution should be used.
- If we have the standard deviation for the population, the z-distribution should be used.
In this problem, σ is not known, hence we get the standard deviation of the sample from the histogram and the t-distribution is used.
Using a t-distribution calculator, considering a <em>confidence level of 99%</em> and 56 - 1 = <em>55 df</em>, the critical value is t = 2.6682.
More can be learned about the t-distribution at brainly.com/question/16162795
Answer: a. reject the null hypothesis, church attendance and marital status are dependent
Step-by-step explanation:
- If the obtained chi-square value is greater than the critical chi square value then we reject the null hypothesis.
Given : A Chi square test has been conducted to assess the relationship between marital status and church attendance. The obtained Chi square is 23.45 and the critical Chi square is 9.488.
Null hypothesis : There is no relationship between the variables.
Alternative hypothesis : There is a relationship between the variables.
Here we can see that the obtained chi-square (23.45) value is greater than the critical chi square value (9.488) , then we have to reject the null hypothesis.
So the correct answer is reject the null hypothesis, church attendance and marital status are dependent.
For an arithmetic sequence, the nth term is the first term plus (n-1)×the differece
the first term is 28, the difference between each adjacent number is 8
so -36=(28)+8(n-1)
8(n-1)=64
n-1=8
n=9
the 9th term is -36
V = 1/3 l h w
V = 1/3 (12)(15)(9)
V= = 540
answer 540 m^3
Answer:
<3 and <4 are supplementary
Step-by-step explanation:
<3 and <4 form a linear pair, so they are supplementary (=180 degrees)
