Answer:
D. y = –6x – 4
Step-by-step explanation:
Find the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line parallel to y
=
−
6
x
+
2
.
y
=
−
6
x
−
4 PARALLEL
...............................................................................................................................................
Find the negative reciprocal of the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line perpendicular to y
=
−
6
x
+
2
.
y
=
1
/6
x
+
13/
6 PERPENDICULAR
Answer:
45
Step-by-step explanation:
2a+3b=15, multiply everything by 3
3(2a+3b)=3(15)
6a+9b=45
Answer:
0.24
Step-by-step explanation:
Answer:
This verified guy is wrong, and all I can say is I resubmitted twice and it's not "He should use the median because it's the center of data" or "He should use the mean because there are no outliers that affect the mean."
Step-by-step explanation:
Actually, it's MEDIAN because there ARE outliers that affect the MEAN. If you take the mean, average, then the $2.5 M house will raise the mean.
Using the z-distribution, the confidence interval is given by: (11.95, 12.65).
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
![\overline{x} \pm z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%20%5Cpm%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.645.
The other parameters are given as follows:
![\overline{x} = 12.3, \sigma = 1.5, n = 50](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%20%3D%2012.3%2C%20%5Csigma%20%3D%201.5%2C%20n%20%3D%2050)
Hence the bounds of the interval are:
![\overline{x} - z\frac{\sigma}{\sqrt{n}} = 12.3 - 1.645\frac{1.5}{\sqrt{50}} = 11.95](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%20-%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%2012.3%20-%201.645%5Cfrac%7B1.5%7D%7B%5Csqrt%7B50%7D%7D%20%3D%2011.95)
![\overline{x} - z\frac{\sigma}{\sqrt{n}} = 12.3 + 1.645\frac{1.5}{\sqrt{50}} = 12.65](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%20-%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%2012.3%20%2B%201.645%5Cfrac%7B1.5%7D%7B%5Csqrt%7B50%7D%7D%20%3D%2012.65)
More can be learned about the z-distribution at brainly.com/question/25890103
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