Describe how you would find an object that is about 8 inches long

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

6 0

I would take a 12 inch ruler and measure some this that is larger than your palm.

Hoochie [10]3 years ago

4 0

Bye measuring by a ruler or something that is equivalent to 8 inches<span />

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What is this question

xeze [42]

well, p + (-2), now a sign in front of a grouping symbol usually means it has a 1*, so +(, really means +1*, thus p + (-2) really means p + 1*(-2), which gives us p - 2, and that'd be ordinally, 2 numbers to the left of "p".

likewise, 5 + p, is just the same as p + 5, so that value will be a number 5 numbers to the right of "p".

just as above, p + 1, is just one value to the right of "p".

$\bf \rule[0.35em]{2em}{0.25pt}\stackrel{p-2~\hfill }{|\rule[0.35em]{2em}{0.25pt}}|\rule[0.35em]{2em}{0.25pt}\boxed{P}\stackrel{~\hfill p+1}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\rule[0.35em]{2em}{0.25pt}|\stackrel{~\hfill p+5}{\rule[0.35em]{2em}{0.25pt}|}\rule[0.35em]{2em}{0.25pt}|$

4 0

2 years ago

Flight 202's arrival time is normally distributed with a mean arrival time of 6:30 p.m. and a standard deviation of 15 minutes.

natta225 [31]

Answer:

The probability is 0.0015

Step-by-step explanation:

We know that the mean $\mu$ is:

$\mu=6:30\ p.m$

The standard deviation $\sigma$ is:

$\sigma=0:15\ minutes$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

We seek to find

$P(x>7:15\ p.m.)$

The Z-score is:

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{7:15-6:30}{0:15}$

$Z=\frac{0:45}{0:15}$

$Z=3$

The score of Z = 3 means that 7:15 p.m. is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

$P(x>7:15\ p.m.)=P(Z>3)=0.0015$