Answer:
#1 - Two complementary angles with measures that have a sum of 90.
#2- angles with a common vertex and side.
#3 - two supplementary angles with measures that have a sum of 180.
#4 - the region of a plane inside an angle
#5 - the region of a plane outside an angle
#6 - an angle with a measure of anything less than 90 degrees.
#7 - an angle with a measure of anything greater than 90 degrees.
These all should be right :)
Lmk how I did!
<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
Answer:
∠B = 62°
Step-by-step explanation:
Because ∠A and ∠B are vertical angles they are equal hence we can write
∠A = ∠B
8x + 14 = 2x + 50
Now we have to solve for x
To do so, subtract 2x on both sides of the equation:
6x + 14 = 50
Now, subtract 14 on both sides of the equation
6x = 36
Now, divide 6 on both sides of the equation
x = 6
To find m∠B you have to you have to plug in x = 6 back into the ∠B equation
∠B = 2(6) + 50
∠B = 62°
Was there a chart with this?
