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garri49 [273]
2 years ago
11

Two bicycle wheels are shown below which is closest to the circumference in inches of the larger wheel.

Mathematics
1 answer:
olganol [36]2 years ago
7 0
We estimate the diameter of the larger wheel to be 24 to 25 inches.

The formula for the Circ. of a circle in terms of the diameter is C = pi*d.

Here, the Circ. of the larger wheel is approx C = pi(24 inches) = 24*pi inches,
or 

24(3.14) inches = 75.36 inches.   You must now choose from the four answer choices.  Which one is closes to 75.36 inches?
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Factor the quadratic expression completely 15x^-4x-4
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Answer:

(5x+2)(3x-2)

Step-by-step explanation:

4 0
2 years ago
Is the answer 3, 4, 5, or 6? need answer asap please! :)
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Don't touch the center. It is already even. 
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.

Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.

Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2 
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3 <<<< answer
4 0
2 years ago
What is 4.58 when approximated to the nearest hundredth
Ann [662]

Answer:

The answer would be 4.6

Step-by-step explanation:

4.58

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6 0
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Read 2 more answers
7th grade math help me pleasee
irinina [24]

Answer:

15 degrees Celsius

Step-by-step explanation:

5 0
2 years ago
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Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
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