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MAXImum [283]
3 years ago
10

Which is the quotient of 1.54 + 0.44 ?

Mathematics
1 answer:
Anestetic [448]3 years ago
3 0

Answer

1.98

Step-by-step explanation:

1.54 + 0.44 = 1.98

hope it helps.

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Let g(x)=3x<br><br> g(g(g(-1)))
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Answer:

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4 0
3 years ago
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A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and
goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}

Solve for S(t):

\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}

e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}

The left side is the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}

Integrate both sides:

e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt

e^{t/800}S(t)=64e^{t/800}+C

S(t)=64+Ce^{-t/800}

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

0=64+C\impleis C=-64

and so (b) the amount of sugar in the tank at time t is

S(t)=64\left(1-e^{-t/800}\right)

As t\to\infty, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

7 0
4 years ago
The length of a picture frame is 7 inches more than the width. For what values of x is the perimeter of the picture frame greate
makkiz [27]
P=2(L+W)
l=x+7
w=x
P=2(x+7+x)
P=2(2x+7)
P=4x+14

hast to be greater than 154

P>154
4x+14>154
minus 14 both sides
4x>140
divide 4
x>35


4 0
4 years ago
in your math class there are 2 Boys for every 3 girl.which of the following be the ratio of Boys and girl in the class?​
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Answer:

B. 14/21

Step-by-step explanation:

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How many gallons of a 90% antifreeze solution must be mixed with 100 gallons of 30% antifreeze to get a mixture that is 80% anti
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The answer for this question would be 30%
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