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Korvikt [17]
3 years ago
15

A bakery works out a demand function for its chocolate chip cookies and finds it to be q = D (x) = 943 - 17 x​, where q is the q

uantity of cookies sold when the price per​ cookie, in​ cents, is x.
A) Find the elasticity.
B) At what price is the elasticity of demand equal to 1?
C) At what prices is the elasticity of demand elastic?
D) At what prices is the elasticity of demand inelastic?
E) At what price is the revenue a maximum?
F) At a price of 21c per cookie, will a small increase in price cause the total revenue to increase or decrease?
1. Increase
2. Decrease
Mathematics
1 answer:
Alex73 [517]3 years ago
5 0

Answer:

See expla below

Step-by-step explanation:

Given the demand function:

q = D (x) = 943 - 17 x

a) Find the elasticity:

Find the derivative of the demand function.

D'(x)= -17

Thus, elasticity expression is:

\frac{x D'(x)}{D'(x)}

= \frac{x (-17)}{943 - 17x}

= \frac{17x}{943 - 17x}

Elasticity expression = E(x) = \frac{17x}{943 - 17x}

b) At what price is the elasticity of demand equal to 1?

This means E(x) = 1

Substitute 1 for E(x) in the elasticity equation:

E(x) = \frac{17x}{943 - 17x}

1 = \frac{17x}{943 - 17x}

Cross multiply:

943 - 17x = 17x

Collect like terms

17x + 17x = 943

34x = 943

x = \frac{943}{34}

x = 27.74

Elasticity at the price of demand = 1 is 27.74

c) At what prices is the elasticity of demand elastic?

This means E(x) > 1

Therefore,

\frac{17x}{943 - 17x} > 1

\frac{17x}{943 - 17x} > 1

Cross multiply:

17x > 943 - 17x

Collect like terms

17x + 17x > 943

34x > 943

x > \frac{943}{34}

x > 27.74

The elasticity of demand is elastic at x > 27.74

d) At what prices is the elasticity of demand inelastic?

This means E(x) < 1

Therefore,

\frac{17x}{943 - 17x} < 1

\frac{17x}{943 - 17x} < 1

Cross multiply:

17x < 943 - 17x

Collect like terms

17x + 17x < 943

34x < 943

x < \frac{943}{34}

x < 27.74

The elasticity of demand is inelastic at x < 27.74

e) At what price is the revenue a maximum:

Total  revenue will be:

R(x) = x D(x)

= x (943 - 17x)

= 943x - 17x²

R(x) = 934 - 17x(price that maximizes total revenue)

Take R(x) = 0

Thus,

0 = 943 - 17x

17x = 943x

x = \frac{943}{17}

x = 27.74

Total revenue is maximun at x= 27.74 per cookie

f) At x = 21 per cookie, find the price:

Thus,

R (21) = (943 * 21) - (17 * 21²)

= 19803 - 7497

= 12306

At x = 27.74, find the price:

R(27.74) = (943 * 27.74) - (17 - 27.74²)

= 26158.82 - 13081.63

= 13077.19

We can see the new price of cookie causes the total revenue to decrease.

Therefore, with a small increase in price the total revenue will decrease.

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Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

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f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

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x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

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f(7.9225) = 2.0697 + 7.9225 -10

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x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

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