Answer:
E
Step-by-step explanation:
Solution:-
- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.
- The survey team took a sample of size n = 24 students and obtained the following results:
Sample mean ( x^ ) = 12.3 mins
Sample standard deviation ( s ) = 3.2 mins
- The sample taken was random and independent. We can assume normality of the sample.
- First we compute the critical value for the statistics.
- The z-distribution is a function of two inputs as follows:
- Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025
Compute: z-critical = z_0.025 = +/- 1.96
- The confidence interval for the population mean ( u ) of walking times is given below:
[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]
Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]
Answer:
The estimate of In(1.4) is the first five non-zero terms.
Step-by-step explanation:
From the given information:
We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)
So, by the application of Maclurin Series which can be expressed as:
Let examine f(x) = In(1+x), then find its derivatives;
f(x) = In(1+x)
f'(0) 
f ' ' (x) 
f ' ' (x) 
f ' ' '(x) 
f ' ' '(x) 
f ' ' ' '(x) 
f ' ' ' '(x) 
f ' ' ' ' ' (x) 
f ' ' ' ' ' (x) 
Now, the next process is to substitute the above values back into equation (1)
To estimate the value of In(1.4), let's replace x with 0.4
Therefore, from the above calculations, we will realize that the value of 
as well as 
which are less than 0.001
Hence, the estimate of In(1.4) to the term is 
is said to be enough to justify our claim.
∴
The estimate of In(1.4) is the first five non-zero terms.
To answer you do 5 times 4 times 3 to get 60
Answer:The function v(x) has the largest value when x = 4.
Solution:
x=4;
e(4) = 4^2 + 6×4 + 21=16+24+21=61
m(4) = 8×4=32
v(4) = 31×4=124
v(4)>e(4)>m(4)
Therefore,The function v(x) has the largest value when x = 4.
Answer:
There is not enough information to determine the mean, the median is 28.
There is not enough information to determine the mean absolute deviation, the interquartile range is 18
Step-by-step explanation:
The box plot given has a skewed distribution, this means that both the mean and median values are not the same. From a box plot, the median value Can be obtained as the point in between the box.
From the box plot given, the marked point in between the box is 28 cm
Hence, Median = 28 cm
The mean cannot be inferred from the skewed box plot.
There is also not enough information to determine the mean absolute deviation ;
The interquartile range:
(Q3 - Q1)
Q3 = upper quartile, the endpoint of the box = 40
Q1 = the starting point of the box = 22
IQR = Q3 - Q1
IQR = 40 - 22 = 18
