T(n)=6-1=5
that means all terms are 5 because n does not appear on the right hand side.
However, if T(n)=6n-1, then
first term = T(1)=6(1)-1=5,
but second term T(2)=6(2)-1=11...
Answer:
x = 2
Step-by-step explanation:
I just chucked it into Wolfram Alpha and it showed me x = 2
also for more proof, insert positive 2 in both x's
Answer:
Step-by-step explanation: Step 1: Isolate the absolute value expression.
Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.
Step 3: Solve for the unknown in both equations.
Step 4: Check your answer analytically or graphically.
I'm willing to help you with both parts
<span>We cannot deduce about the exact location of P between J and K. But we can conclude: segment JP + segment PK = line JK.
</span><span>JP + PK = JK.
</span><span>Substitute first each.
(8z - 17) + (5z + 37) = 17z - 4
Combine like terms.
13z + 20 = 17z - 4
Isolate the variable z.
4z = 24
z = 6
The value of the variable z is then 6 units.</span>
