2 years ago

Choose an absolute value inequality for the situation with the given tolerance.

Mathematics

1 answer:

Serjik [45]2 years ago

4 0

Answer

Im telling ms dennis

You might be interested in

Kennedy lives in the middle of the city. Her friend Zoe lives 8 miles to the west and her friend Shiloh lives 6 miles to the sou

Kamila [148]

Answer:

i would say about 16 miles.

5 0

2 years ago

Read 2 more answers

Need help now!! 20 points!!

Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

3(56)+2(1)

168+2

170

3 0

2 years ago

Thabo invests R50000 at the rate of 5% per annum compound interest periodically every six months.How many years does it take to

lina2011 [118]

Answer:

50000-5%=49500 pls like

7 0

2 years ago

Given roots of quadratic equation are x=3 and x=4 write the quadratic equation.

Andrews [41]

Asome that’s cool do well

6 0

2 years ago

Can someone help me with this ?

romanna [79]

Answer:

$\large\boxed{S.A.=467\ in^2}$

Step-by-step explanation:

We have two triangles and three rectangles.

The formula of an area of a triangle:

$A_{triangle}=\dfrac{bh}{2}$

b - base

h - height

The formula of an area of a rectangle:

$A_{rectangle}=lw$

l - length

w - width

TRIANGLE:

b = 11 in, h = 7 in

$A_1=\dfrac{(11)(7)}{2}=\dfrac{77}{2}=37.5\ in^2$

RECTANGLE 1:

l = 11 in, w = 14 in

$A_2=(11)(14)=154\ in^2$

RECTANGLE 2:

l = 9 in, w = 14 in

$A_3=(9)(14)=126\ in^2$

RECTANGLE 3:

l = 8 in, w = 14 in

$A_4=(8)(14)=112\ in^2$

The Surface Area:

$S.A.=2A_1+A_2+A_3+A_4$

Substitute:

$S.A.=2(37.5)+154+126+112=467\ in^2$

6 0

2 years ago