Answer:
22.9 Liters CO(g) needed
Explanation:
2CO(g) + O₂(g) => 2CO₂(g)
? Liters 32.65g
= 32.65g/32g/mol
= 1.02 moles O₂
Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)
∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)
Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.
∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed
___________________
*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).
<span>6.37x10^-30 coulomb-meters
The unit for dipole moments is the Debye which is 1x10^-21 C*m^2/s divided by the speed of light (299792458 m/s). So the conversion factor is
1x10^-21 C*m^2/s / 299792458 m/s = 3.33564095E-30 C*m
And converting 1.91 d to Cm gives
1.91 * 3.33564095E-30 C*m = 6.37x10^-30 coulomb-meters</span>
Answer:
I think you meant metabolism
Explanation:
me·tab·o·lism
the chemical processes that occur within a living organism in order to maintain life.
Solid Magnesium is considered as active metal so it reacts with strong acids like HCl and H₂SO₄ liberating Hydrogen gas according to the following equations:
Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
Mg(s) + H₂SO₄(aq) → MgSO₄(aq) + H₂(g)
so the amount of solid magnesium decrease by addition of strong acid to it.
Answer: Thus 8.41 g was the mass of the original sample
Explanation:
To calculate the moles :
According to stoichiometry :
As 3 moles of 
are produced by = 2 moles of 
Thus 0.103 moles of are produced by =
of
Mass of 
Thus 8.41 g was the mass of the original sample.
