Identify the appropriate reagent (A-H) you would use to accomplish the given transformation. A. MeONa B. H2, Pt C. t-BuOK D. 1)
Hg(OAc)2, H2O; 2) NaBH4 E. HBr F. HBr, ROOR G. HCl H. 1) BH3-THF; 2) H2O2, NaOH
1 answer:
(See full question in attachment)
Answer:
A. MeONa
Explanation:
One of the methods to prepare alkenes are eliminations.
The E2 reaction (for elimination, bimolecular) occurs when an alkyl halide is treated with a strong base, such as hydroxide ion or alkoxide ion (RO⁻).
It is the most common mechanism that occurs for an elimination.
The methoxide ion is a strong base that will attack the neighboring hydrogen of the halide ion and will start removing H⁺ at the same time that the double bond of the alkene begins to form and the group X begins to leave.
Then, the neutral alkene is produced when the C – H link and X group has left with the electron pair of the bond C – X (mechanism in attachment).
Therefore, MeONa would be an appropiate reagent.
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<h2>Hello!</h2>
The answer is:
The percent yield of the reaction is 32.45%
<h2>Why?</h2>To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.
We are given that:
Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.
So, calculating we have:
Hence, we have that the percent yield of the reaction is 32.45%.
Have a nice day!