[tex] 3x+12-4x-16 \\ (3x-4x) + (12-16) \\ -x -4 \\ x+4 [tex]
Answer:
-10 < x < -8
Step-by-step explanation:
Envision a number line. There is one whole number, -9, and and an infinite amount of fractions (rational numbers) and irrational numbers between -10 and -8.
X could be any of those values.
5 to 12. All you do is switch the ratios around.
Answer:
43.5 cm² and 112 cm²
Step-by-step explanation:
Here the instructions aren't given what to do. So I am finding the area of the ∆s .
<u>Area </u><u>of</u><u> </u><u>first </u><u>∆</u><u> </u><u>:</u><u>-</u><u> </u>
- A = 1/2 * b * h
- A = 1/2 * 14.5 cm * 6cm
- A = 3 × 14.5 cm²
- A = 43.5 cm²
<u>Area </u><u>of</u><u> </u><u>second</u><u> </u><u>∆</u><u> </u><u>:</u><u>-</u><u> </u>
- A = 1/2 * ( sum of || sides) * h
- A = 1/2 * ( 9 cm + 19cm) * 8cm
- A = 4cm * 28cm
- A = 112 cm²
Answer:
B. All squares are rectangles.
Step-by-step explanation:
B is the correct answer, because all the squares are rectangles have 4 sides.