Answer:
The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the sum of the numbers in the six outer circles of the star, must be equal to 26. Arrange the numbers accordingly.
By clearly looking at the sequence there are in Arithmetic Progression
So for finding which term is 2218 in that sequence
we have x_{n} = a+ (n-1)d
Here,
a=3
x_{n}=2218 & d=5(by looking at the sequence given)
by substituting those values we get our desired result
2218=3+(n-1)5
2218-3=(n-1)5
2215=(n-1)5
2215/5=n-1
453=n-1
n=454
so 454 term is 2218
The answer is 45.6 u need to find out the base and length and there u go
The picture would change the distance from the bridge, the ground, and the jumper.
