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34kurt
4 years ago
7

Find the speed at which Superman (mass=76.0 kg) must fly into a train (mass = 19969 kg) traveling at 65.0 km/hr to stop it.

Physics
1 answer:
yawa3891 [41]4 years ago
4 0
A, speed = 70 km/h x (17026/79) =15086 km/h b, v=u +at v=0, a=-0.5 g = -4.9 m/s^2 u=19.4 m/s t = 3.96 s c, v^2 = u^2 + 2 as as above, 19.4^2 = 2 *0.5 *g *s s = 19.4^2/9.8 = 38.6m

Hope it helps :)



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Is friction an advantage in braking
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Yes, Sliding Friction Stops a Car. When you apply the brakes of a car, sliding friction helps to stop it. ... The surface of the drum or rotor slide against the brake disc or pad, which is a force of friction that slows the vehicle down.

4 0
3 years ago
__________ are scientists that study the composition of earth including rock layers at the surface.
insens350 [35]

Answer:

Geology is the study of planet Earth, including its composition and structure. Geologists are scientists who study Earth and the processes that shape Earth over time. Geologists study two types of forces that change Earth's surface.

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4 0
3 years ago
2
Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

\displaystyle U_i = K_f

Substitute and solve for final velocity:
\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\  2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ &  =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0
2 years ago
What would occur if there was a gain-of-function mutation in the promoter for the cyclin E gene such that cyclin E protein was a
rjkz [21]

Answer:

b) Cells will pass through the G1/S checkpoint even if conditions are not ideal for cell division.

Explanation:

In the given problem, if there exists a gain-of-function mutation for the given cell, there would not be the formation of cyclin E when there is the possibility of cells movement via the checkpoint of the G1/S, even when there are non-deal conditions for the division of cell. Thus, the correct option in the lists of options is the option b.

7 0
4 years ago
A raft of mass 199 kg carries two swimmers of mass 52 kg and 70 kg. The raft is initially floating at rest. The two swimmers sim
Minchanka [31]

To solve this problem we will apply the concept related to the conservation of the Momentum. We will then start considering that the amount of initial momentum must be equal to the amount of final momentum. Considering that all the objects at the initial moment have the same initial velocity (Zero, since they start from rest) the final moment will be equivalent to the multiplication of the mass of each object by the velocity of each object, so

Initial Momentum = Final Momentum

(m_B+m_1+m_2)v_i = m_1v_1+m_2v_2+m_Bv_B

Here,

m_B =  mass of Raft

m_1 = Mass of swimmers 1

m_2 = Mass of swimmers 2

v_i = Initial velocity (of the three objects)

v_B = Velocity of Raft

Replacing,

(199+52+70)*0 = (52)(4)+(70)(-4)+199v_B

Solving for v_B

vB = \frac{72}{199}

v_B = 0.3618m/s

Therefore the velocity the rarft start to move is 0.3618m/s

5 0
4 years ago
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