Answer:
The gravity is pulling the diver downwards but the rotation of the body means gravity cant pull him down as quickly
Explanation:
First step is to convert the lb to kg as follows:
1 lb = 0.45 kg
Therefore, 150 lb = 150 x 0.45 = 67.5 kg
Avogadro's number = 6.02 x 10^23
Mass of Avogadro's number of people = 6.02 x 10^23 x 67.5
= 4.0635 x 10^25 kg
The planet of an item will remain constant across the planet, but if you give it more mass, the gravitational force increases while the acceleration due to gravity remains constant.
<h3 /><h3>What is the difference between mass and weight?</h3>
The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg. Mass is the quantity on which a lot of physical quantity depends.
Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.
Mass is an independent quantity it never depends on the other. While weight is a dependent quantity that depends upon the gravitational pull.
The value of gravitational pull is different in the different parts of the universe. For example, on the earth, the value of gravitational acceleration is 9.81 m/sec².While on the moon it is g/6.
Weight is change according to the place or surrounding while the mass of the body is constant everywhere.
The planet of an item will remain constant across the cosmos, but if you give it more mass, the gravitational force increases while the acceleration of gravity remains constant.
If a planet's gravity weakens, the weight of that planet will likewise be altered. With an increase in mass, weight also rises.
Hence, the gravitational force increases while the acceleration due to gravity remains constant for the given case.
To learn more about the mass refer to the link;
brainly.com/question/19694949
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Answer:
The mass of the meter stick is 
Explanation:
Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero
Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at 
Now lets consider the later case where stick is balanced by two 5.12 g coins .
Here torque due to two coins = 
Torque due to weight of meter stick = 
= 
where m = mass of the meter stick
Here 
.
Upon equating we will be getting mass of the meter stick =
Answer: (a). ΓL = 0.246 < 75°
(b). S = 1.7
(c). Zin = (30-j)λ
(d). jreal = Arc Po = 0.105λ
(e). jmax = jreal = 0.105λ
Explanation:
attached is a document to help in understanding.
So we will begin with a step by step analysis of the problem.
from the diagram we have that ZL = (50 + j25) Ω.
where ZL = ZL / Z₀ = 50 + j25 / 50 = 1 + j0.5
so we mark this on the chart as point 'P'
(a) ΓL = mP/m 'P' < Θ L = 1.7/6.9 < 75°
ΓL = 0.246 < 75°
(b) This s-circle 's' is given thus s = r = 1.7 on the RHS of the chart
S = 1.7
(c) we are to calculate the input impedance;
ζin = Q = 0.6 - j0.02
therefore Zin = Z₀ζin = 50(0.6 - j0.02) = (30-j)λ
Zin = (30-j)λ
(d) here we are taking R as the diameter opposite of Q on the s=circle
so R = γin = 1.7 + j0.02
yin = yo (γin) = (1.7+j0.02) / 50 = (34 + j0.4)ms
yin = (34 + j0.4)ms
(e) move from 'p' on s-circle to 'o'
where maximum impedance = Znxl = Zos
which gives jreal = Arc Po = 0.105λ
(f) jmax = jreal = 0.105λ
cheers i hope this helps
