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Marat540 [252]
2 years ago
15

2

Physics
1 answer:
Xelga [282]2 years ago
8 0

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

\displaystyle U_i = K_f

Substitute and solve for final velocity:
\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\  2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ &  =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

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