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Tems11 [23]
4 years ago
7

With what force will a car hit a tree if the car has a mass of 3,454 kg and it is accelerating at a rate of 5 m/s2?

Physics
1 answer:
nignag [31]4 years ago
3 0

Answer:

F = 17270 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by the acceleration.

ΣF = m*a

where:

F = force [N]

m = mass = 3454 [kg]

a = acceleration = 5[m/s^2]

Now replacing:

F = 3454*5

F = 17270 [N]

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A certain moving electron has a kinetic energy of 0.991 × 10−19 J. Calculate the speed necessary for the electron to have this e
alisha [4.7K]

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Explanation:

Kinetic energy is the energy posessed by an object by virtue of its motion.

K.E=\frac{1mv^2}{2}

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Putting in the values in the equation:

0.991\times 10^{-19}J=\frac{1\times 9.109\times 10^{-31}kg\times v^2}{2}

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4 0
3 years ago
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1. A current of 0.001 A can be felt by the human body. 0.005 A can produce a pain response. 0.015 A can cause a loss of muscle c
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Answer:

It was safe to handle the circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.

Explanation:

Given;

Current of 0.001 A to be felt

Current of 0.005 A can produce a pain response

Current of 0.015 A can cause a loss of muscle control

Total current that traveled in the three-battery circuit = 0.03 A

Thus, we can conclude that, it was safe to handle the above mentioned circuit with dry hands because dry skin body resistance is very high, measuring up to 500,000 ohms.

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The sound from mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time
pashok25 [27]

As per the the question the sound source is the mosquito.

the mosquito produces the sound with the help of its wings

as per the question the wings vibrate at the rate of 500 vibrations per second.

we have been asked to calculate the time period  of vibration.

we know that that time period is the reciprocal of frequency of vibration

hence time period [T]=\frac{1}{frequency}

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hence the time period of the  vibration of the wings of the mosquito is 0.002 second.

6 0
4 years ago
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