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Natasha_Volkova [10]
3 years ago
8

How do you solve Binomial Squares?

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0
Step 1: Square the first term of the binomial. Step 2: Multiply the first term and last term of the binomial together and then double that quantity (in other words multiply by 2). Step 3: Square the last term of the binomial
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Find an equation for the nth term of the arithmetic sequence.<br> 8,6,4,2,…
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Answer:

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Step-by-step explanation:

hope this helps

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Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 &lt; 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

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sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

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The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

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sin(\theta)=-\frac{1}{2}

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\theta=\frac{2\pi}{3},\frac{4\pi}{3}

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Answer:

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Step-by-step explanation:

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