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3 years ago

And here are the answer choices

Mathematics

2 answers:

kifflom [539]3 years ago

8 0

Apt answer is f (x) = 6x^1.5

IRISSAK [1]3 years ago

3 0

The answer is C because that is the I just guessed and hopefully it is correct

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Distribute -2x\left(-10x+1\right).−2x(−10x+1)

ZanzabumX [31]

<h3>I'll teach you how to distribute −2x(−10x+1)</h3>

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−2x(−10x+1)

Apply the distributive law:

Ex. of distributive law:

a(b+c)= ab+ac

-2x(-10x)+(-2x)*1

Apply minus/plus rule:

2*10xx-2*1*x

Simplify 2*10xx-2*1*x:

2*10xx= 20x^2

2*1*x= 2x

20x^2-2x

Your Answer Is 20x^2-2x

plz mark me as brainliest if this helped :)

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3 years ago

How do u express a ratio as a decimal

Viktor [21]

Perform the indicated division ... divide the numerator by the denominator.
The quotient is the decimal form of the ratio.

6 0

3 years ago

Hola estoy a punto de llorar jajaja estoy tan triste y necesito algunos amigos estoy taaaaaaaaaaaaaaaaaaaaaaa

Dafna1 [17]

Answer:

same

Step-by-step explanation:

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3 years ago

Read 2 more answers

-65=6b-11<br><br> hi I don't understand how to solve this equation<br> can someone please explain :)

belka [17]

-65=6b-11

Add 11 to both sides to get rid of the -11 on the right side

-54=6b

Then divide both sides by six to find the value of b

-9=b

So b is -9

7 0

3 years ago

Read 2 more answers

A car's cooling system has a capacity of 20 quarts. Initially, the system contains a mixture of 3 quarts of antifreeze and 17 qu

Pachacha [2.7K]

Answer:

1.10 quarts

Step-by-step explanation:

We are given that

Capacity of system=20 quarts= $\frac{20}{4}=5 gal$

1 gallon=4 quarts

Initially mixture contains

Antifreeze=3 quarts= $\frac{3}{4}=0.75 gal$

Water=17 quarts= $\frac{17}{4}=4.25 gal$

Water runs in to the system=1gal/min

We have to find the antifreeze in the system at the end of 5 minutes.

Concentration inflow=0

Let Concentration outflow=x

Rate of system=Concentration inflow(water inflow rate)-Concentration outflow(water outflow rate)

$\frac{dx}{dt}=0\times 1-\frac{1}{5} x=-\frac{x}{5}$

$\frac{dx}{x}=-\frac{dt}{5}$

Taking integration on both sides

$\int\frac{dx}{x}=-\frac{1}{5}\int dt$

$ln x=-\frac{1}{5}t+C$

$x=3 and t=0$

$ln 3=C$

$ln x-ln 3=-\frac{1}{5}t$

$ln\frac{x}{3}=-\frac{1}{5}t$

Using formula

$ln m-ln n=ln\frac{m}{n}$

$\frac{x}{3}=e^{-0.2t}$

$x=3e^{-0.2t}$

Substitute t=5

$x=3e^{-0.2\times 5}=3e^{-1}=1.10$

Hence, in the end of 5 minute ,the antifreeze in the system=1.10 quarts

7 0

4 years ago