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Licemer1 [7]
3 years ago
7

At a store, there is a display of 240 boxes of cereal. of the 240 boxes, 3/5 are brand A and 2/5 are brand B. How many boxes of

brand B cereal must be added so that the display has 1/2 of each brand?
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0
240(3/5) = 144
240(2/5) = 96

144-96 = 48

48 boxes must be added


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How do you write 3.25 in simplest form
dedylja [7]
3.25 would be 3 1/4 because,

Step 1: You would rewrite the decimal number as a fraction with 1 in the denominator. So, 3.25 = 3.24/1

Step 2: Multiply it by 1 to eliminate 2 decimals places, so multiply the top and bottom by 10^2 = 100
3.25/1 x 100/100 = 325/100
Step 3: Now you find the greatest common factor, also known as GCF, of 325 and 100 if it exits then you reduce the fraction by dividing both numerator and denominator by it. GCF = 25
3.25/100 divided by 25/25 = 13/4
Now you would simplify it to make a proper fraction getting your answer
3 1/4
Does that make sense?
7 0
3 years ago
Read 2 more answers
ASAP PLZ IM TIMED I WILL GIVE BRAINLIEST ​
katrin [286]

Step-by-step explanation:

{ \huge{ \red{ \bf( \frac{3}{4} ) {}^{3} }}}

{ \huge{ \blue{ \bf{( \frac{3 \times 3 \times 3}{4 \times 4 \times 4} )}}}}

{ \large{ \pink{ \boxed{ \tt{ \bigg( \frac{27}{64} { \bigg)}}}ans.}}}

3 0
2 years ago
What is the perimeter of this triangle?
salantis [7]

3w-15 is the answer ,

w + w + w-15

( combime like terms )

= 3w - 15


6 0
3 years ago
What dose this equal 2(6x-4)=3(6x+2)
AveGali [126]

Answer:

-7/3

Step-by-step explanation:

2(6−4)=3(6+2)

2(6x-4)=3(6x+2)

Solve

1

Distribute

2(6−4)=3(6+2)

{\color{#c92786}{2(6x-4)}}=3(6x+2)

12−8=3(6+2)

{\color{#c92786}{12x-8}}=3(6x+2)

2

Distribute

12−8=3(6+2)

12x-8={\color{#c92786}{3(6x+2)}}

12−8=18+6

12x-8={\color{#c92786}{18x+6}}

3

Add

8

8

to both sides of the equation

12−8=18+6

12x-8=18x+6

12−8+8=18+6+8

12x-8+{\color{#c92786}{8}}=18x+6+{\color{#c92786}{8}}

5 more steps

Solution

=−7/3

7 0
2 years ago
Read 2 more answers
Simplify 5+2i/6+i
nlexa [21]

Given problem is \frac{(5+2i)}{(6+i)}

To simplify that we need to multiply and divide by conjugate of the denominator

conjugate of denominator 6+i will be 6-i as we just need to change sign of the imaginary part

Now multiply and divide by 6-i


=\frac{(5+2i)}{(6+i)}\cdot\frac{(6-i)}{(6-i)}

=\frac{30-5i+12i-2i^2}{36-6i+6i-i^2}

=\frac{30+7i-2i^2}{36-i^2}

=\frac{30+7i-2\left(-1\right)}{36-\left(-1\right)}

=\frac{30+7i+2}{36+1}

=\frac{32+7i}{37}

=\frac{32}{37}+\frac{7}{37}i

Hence final answer is \frac{32}{37}+\frac{7}{37}i

3 0
3 years ago
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