A. (m+n)(x)=
5x+4+6x-9=
11x-5
B. (mn)(x)=
(5x+4)(6x-9)=
30x^2+24x-45x-36=
30x^2-21x-36
C. basically sub n(x) for x in m(x)
m(n(x))=
5(6x-9)+4=
30x-45+4=
30x-41
Answer:
B.) C.) E.)
Step-by-step explanation:
Hours : logs
4 : 6
18 : x
x/6 = 18/4
4 × x = 6 × 18
x/18 = 6/4
18/x = 4/6
Answer:
0.375 is answer
Step-by-step explanation:
Given that the math teacher gave her students two tests. On the first test, 80% of the class passed the test. But only 30% of the class passed both tests.
Let A - the students pass I test
B = students pass second test
Then P(A) = 80%=0.8 and P(AB) = 30% =0.30
Required probability =probability that a student passes the second test, given that they passed the first one
= P(B/A) = P(AB)/P(A)
= 0.30/0.80
=3/8
=0.375
Right answer is 0.375
Can u specify more pleasee