How do I simplify this expression using the rules of exponents?

It takes 4 pounds of apples to make 6 cups of applesauce.

Serjik [45]

Answer:

Step-by-step explanation:

4lbs of apples to 6 cups of apple sauce

we can write this as 2:3

the correct choices: 6:9 and 14:21

4 0

3 years ago

A moving company charges $0.70 per pound for a move from New York to Florida. A family estimates that their belongings weigh abo

mamaluj [8]

First, how many pounds are equal to 1 ton? 2000

Then, $0.70 x 2000 pounds

So, the cost to move is $1,400

Yep. It's that simple. :)

5 0

3 years ago

LESSON

bagirrra123 [75]

C is the answer hope that helps have a good day

5 0

3 years ago

Please help its urgent

ankoles [38]

450/30

15

15/3x =5

x= 5

5+2y= 315

5-5+2y =315-5

2y = 310

2y/2 = 310/2

y=155

Step-by-step explanation:

450/45

10

2x+4y=450

2×5=10

10+(4×155)

=620/155

=4

10/5=2

3 0

3 years ago

The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand

Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 18.6, \sigma = 5.9$

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 18.6}{5.4}$

$Z = 0.44$

$Z = 0.44$ has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have $n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768$