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Aleksandr [31]
4 years ago
6

Write the domain and range as an inequality please!!! 

Mathematics
1 answer:
Nat2105 [25]4 years ago
5 0

Answer:

x > -1

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

From the graph we can see that our x-values span from -1 to infinity. Since -1 is open dot, it is not included in the domain:

(-1, ∞) or x > -1

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How do I find domain and range from a graph/equation?
likoan [24]

domain represents the x values so for example in a diagonal line that continues infinitely, the domain is all real numbers or (-infinity, infinity)

range represents y values so it would also be all real numbers or (-infinity, infinity)

let’s say there is a line (refer to pic) that moves ONLY from point (-3, -1) and (2, 2)

the domain would be [-3, 2]

we use brackets because it’s a real number unlike infinity (also because it’s a closed circle on the graph; if the graph had an open circle you would use a parenthesis)

and the range would be [-1, 2]

if you have any more questions about this explanation feel free to ask!

3 0
3 years ago
Pleasee help me!!!!!!!
Keith_Richards [23]

Answer:

one second

Step-by-step explanation:

6 0
3 years ago
How many oz of nuts are there in a box that holds 3.2 pounds
melisa1 [442]

Answer:

51.2 oz

Step-by-step explanation:

Stoichiometry

3.2 lb x 16 oz

          ÷ 1 lb      =51.2 oz

3 0
3 years ago
PLEASE HELP!!!!!!!
r-ruslan [8.4K]

Answer:

50 degrees

Step-by-step explanation:

3 x 6 = 18

56 - 18 = 38

38 + 12 = 50

8 0
3 years ago
Solve this system of equations by graphing. First graph the equations, and then type the solution.
stealth61 [152]

Answer:

The solution is the point (1,-4)

Step-by-step explanation:

we have

y=-3x-1 ----> equation A

y=-2x-2 ----> equation B

we know that

The solution of the system of equations by graphing is the intersection point both graphs

using a graphing tool

The intersection point is (1,-4)

see the attached figure

therefore

The solution is the point (1,-4)

5 0
4 years ago
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