$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\A(\stackrel{x_1}{4}~,~\stackrel{y_1}{-7})\qquadB(\stackrel{x_2}{-2}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\AB=\sqrt{[-2-4]^2+[1-(-7)]^2}\implies AB=\sqrt{(-2-4)^2+(1+7)^2}\\\\\\AB=\sqrt{(-6)^2+8^2}\implies AB=\sqrt{36+64}\implies AB=\sqrt{100}\implies AB=10$

8 0

2 years ago

Solve (x + 2) (x + 3) + (x – 3) (x – 2) – 2x(x + 1) = 0<br> x = 5<br> x = 6<br> x = 7<br> x = 8

Anna11 [10]

Answer:

x = 6

Step-by-step explanation:

3 0

2 years ago

The perimeter of a rectangular painting is 244 centimeters. If the width of the painting is 51 centimeters, what is the length?

Schach [20]

Answer:

193 i think

Step-by-step explanation:

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6 0

2 years ago