Y = -3x + 6....the slope here is -3. A parallel line will have the same slope.
y = mx + b
slope(m) = -3
(-4,7)....x = -4 and y = 7
now we sub into the formula and find b, the y int
7 = -3(-4) + b
7 = 12 + b
7 - 12 = b
-5 = b
so ur parallel equation is : y = -3x - 5 <==
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Answer:heyyy there...the answer is b that is -12x^3+12x^2-20
Step-by-step explanation:
<h3>f(x)=
-12x^3+19x^2-5</h3><h3>g(x)=
7x^2+15</h3><h3>f(x)-g(x)=(
-12x^3+19x^2-5)-( 7x^2+15)...{while opening the bracket the sign of the second polynomial changes accordingly}</h3><h3>
it becomes -12x^3+19x^2-5-7x^2-15</h3><h3>
=-12x^3+12x^2-20</h3><h3>
HOPE IT HELPED UUUU</h3>
Answer:
The answer should be A. Y= -4x -9
The equation in slope-intercept is y=0.625x+7.
y = mx + b
where:
m is the slope of the line
b is the y-intercept of the line
The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:
The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:
b = y1 - mx<span>1. hope that helped</span>
