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eimsori [14]
3 years ago
13

When a single card is drawn from an ordinary 52-card deck, find the probability of getting a 2 or a red card?

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0
Let R be the event that a red card is drawn. There are two red suits of 13 cards each, so there are 26 ways of getting are red card. There are 52 cards altogether, so the probability of getting a red card is P(R) = 26 52 = 1 2 . 
http://www.math.ttu.edu/~drager/Classes/02Spring/m1430/anse3.pdf
alina1380 [7]3 years ago
4 0

Answer:

15% chance

Step-by-step explanation:

if you wanna know how s/u

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Cindy wants to send a card and a framed picture in a package.
inn [45]

Answer:

a

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Algebra 2A Help !<br><br> Tadakimasu ~
Ludmilka [50]
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)

first factor into (x-r1)(x-r2)... form

p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)

multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2 

so

p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real

baseically

(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1

7 0
3 years ago
If you flip a coin and roll a 6-sided die, what is the probability that you will flip a tails and roll more than a 3?
pishuonlain [190]
Prob of tails times prob of rolling more than 3
0.5 × 0.5 = 0.25
25%
8 0
3 years ago
Read 2 more answers
What is 49 x 138 - 37 x 49
likoan [24]
49 x 138 = 6762
37 x 49 =1813
6762 - 1813 = 4949 so your answer is 4949.
7 0
3 years ago
Please do a and b and explain
Blizzard [7]

This is a decay problem,

The equation is written as start value x (1 - rate)^tike

Using the information given in the problem:

a) Total = 120(1-0.12)^Hours

b) Replace hours with 19 and solve:

Total = 120(1-0.12)^19

Total = 120(0.88)^19

Total = 10.57674 mg

Round the answer as needed.

4 0
3 years ago
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