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tatuchka [14]
3 years ago
12

at a certain time of day a person 6 ft tall cast a 4 ft shadow how long is the shadow cast by ba 21 ft tree at the same time?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0
Use the cross products rule. 6/4 = 21/x. You will get 6x = 84. Divide both sides by 6 to get x = 14 feet.
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If you want a fast explanation

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If you check the vertices points those indicates the length of 2a thus thatll be 6

To get the center just use middle point equation and you'll get (1,3)

Just to know, a indicates the distance from the center to the vertices, b indicates how wide the hyperbole box is, and c indicates the distance from center to focis

A=3

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We use Pythagoras so

b =  \sqrt{(6) ^{2}  - (3) ^{2}  }

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b =  \sqrt{27}

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Step-by-step explanation:

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Answer:

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32549 = 32550 to 4 significant figures

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Step-by-step explanation:

1.6962 = 1.70 (2 dp)

0.4247 = 0.425 to 3 dp

0.007395 = 0.007 to 3 dp

0.007395 = 0.0074 to 4 dp

32549 = 32500 to 3 significant figures

32549 = 32550 to 4 significant figures

909520 = 910000 to 3 significant figures

909520 = 909500 to 4 significant figures

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