Answer:
k is 2/3 and y is -1/3 when x is -0.5.
Step-by-step explanation:
The direct variation relationship is y = kx, where k is the const. of var.
Subbing 3 for x and 2 for y, 2 = 3k, or k = 2/3.
Now, if x = -0.5, y = (2/3)(-1/2) = -1/3
k is 2/3 and y is -1/3 when x is -0.5.
37. 6r^2
41. B
42. B
44. C
Answer:
(-5, 0) ∪ (5, ∞)
Step-by-step explanation:
I find a graph convenient for this purpose. (See below)
__
When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...
f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)
This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).
Step-by-step explanation:
expanded notation form. 10+3+0.6+0.05+0.002
expanded factor form. 1x10+3×1+6x0.1+5×0.01+2×.001
exponential form 1x10^1 + 3x10^0 + 6x10^-1 + 5x10^-2 + 2x10^-3
word form is thirteen and six hundred fifty-two thousandths
Answer:
a:vertex angle
Step-by-step explanation:
it is vertex angle