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lbvjy [14]
3 years ago
13

Show that y = 11x + 5 is a tangent to the curve y = 3x² + 5x + 8

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

There is only 1 solution for x.

Step-by-step explanation:

Hi there!

y = 11x + 5

y = 3x^2 + 5x + 8

This is a linear-quadratic system. If the line is tangent to the parabola, it means that it would only have 1 solution.

Set y equal:

3x^2 + 5x + 8= 11x + 5

Move everything to the left side:

3x^2 + 5x + 8-11x-5=0\\3x^2 -6x + 3=0

Divide both sides by 3:

x^2 -2x + 1=0

Factor:

(x-1)^2=0

Solve for <em>x</em>:

x-1=0\\x=1

Therefore, the only solution for x when y is set equal for both functions is 1. There is only 1 solution for x, so y = 11x + 5 is tangent to the curve y = 3x^2 + 5x + 8.

I hope this helps!

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