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Dennis_Churaev [7]
3 years ago
6

Out of 100 emails, 60 are spam and 48 of those contain the word buy. Of the remaining 40 emails that are not spam, only 4 emails

contain the word buy. Given that an email is spam, what is the probability that it contains the word buy?
{this is a Plato geometry B question!}

A.]0.80
B.] 0.87
C] 0.92
D.] 0.97
Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0

Answer:

A:80

Step-by-step explanation:

Took the test and got it right.

wel3 years ago
5 0

Answer with Step-by-step explanation:

                               Contain Buy              Do not contain Buy        Total

Spam                           48                                    12                             60

Not Spam                     4                                     36                             40

P(it contains the word buy and it is spam)=48/100

P(It is spam)=60/100

Baye's theorem states that:

P(A given B)=P(A∩B)/P(B)

P( it contains the word buy, Given that an email is spam)

=P(it contains the word buy and it is spam)/P(It is spam)

= 0.48/0.60

=0.80

Hence, Correct option is:

A.] 0.80

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8 0
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torisob [31]
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4 0
3 years ago
What’s the third side?
romanna [79]
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6 0
3 years ago
Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm
GuDViN [60]
Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones). 

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

P(x \ \textless \  3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \  3) \approx 0.00951836732 }


Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.


5 0
3 years ago
Is -9 a solution of -9f=90-f
Fantom [35]

Answer:

f = -11.25

Step-by-step explanation:

-9f = 90 - f

-8f = 90

f = 90 / -8

f = -11.25

6 0
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