Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
10 pieces of silverware laid in a row if 3 are identical spoons, 4 are identical forks, and 3 are identical knifes
The arrangement of 'm' objects on which 'n' objects are of same kind is 
Given: 10 pieces of silverware so its 10!
3 are identical spoons so its 3!
4 are identical forks so its 4!
and 3 are identical knifes so its 3!
Arrangements made =
= 4200