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Sergeu [11.5K]
3 years ago
10

You have just used a command that produced some interesting output on the screen. You would like to save that information into a

file named "interesting.txt", which does not currently exist. You can do this by issuing the same command, but appending which of the following?
A. > interesting.txt
B.
C. interesting.txt
D. | interesting.txt
Computers and Technology
1 answer:
Bogdan [553]3 years ago
6 0

Answer: A. > interesting.txt

Explanation: From the command line, one can perform numerous tasks from navigating into a directory, creating a new directory, deleting files, create files, modify files and so on using simple commands. In the scenario above, after using a common which is used to produce an output on the screen, such as the 'echo' command, one may wish to save the file giving the user the ability to access the file later. Since it is stated the file name 'interesting.txt' given to the file does not currently exist, appending the sign > saves the file. If the filename already exists, it will overwrite the existing content.

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four quantum numbers that could represent the last electron added (using the Aufbau principle) to the Argon atom. A n = 2, l =0,
marshall27 [118]

Answer:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2

Explanation:

Argon atom has atomic number 18. Then, it has 18 protons and 18 electrons.

To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

  • 1s² 2s² 2p⁶ 3s² 3p⁶   : 2 + 2 + 6 + 2 + 6 = 18 electrons.

The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

  • n = 3

  • l = 1 (orbitals s correspond to l = 0, orbitals p correspond to l  = 1, orbitals d, correspond to l  = 2 , and orbitals f correspond to  l = 3)

  • m_l can be -1, 0, or 1 (from - l  to + l )

  • the fourth quantum number, the spin can be +1/2 or -1/2

Thus, the six possibilities for the last six electrons are:

  • (3, 1, -1 +1/2)
  • (3, 1, -1, -1/2)
  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
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