Using the knowledge of pseudocodes it will be possible to write a code that calculates the amount of hours worked and giving warnings about it.
<h3>Writing a pseudocode we have that:</h3>
<em>while </em>
<em>if number == 0</em>
<em>break</em>
<em>hours =0 </em>
<em>for i =1 to 5 </em>
<em>hours = hours + time_out[ i ] - time_in[ i ]</em>
<em> If hours >36 : </em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Congratulaion! Your working hours are more than 36")</em>
<em>If hours <30 : #</em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Warning !!!")</em>
<em>End loop</em>
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The answer is Benching.
Benching and sloping are methods used to protect employees working in excavations from cave–ins. Benches are cuts in the slope that provides protection by removing material at an angle to its floor. They give the slope a stair-step appearance with emphasis on the angles; the flatter the angle, the more the protection. Benches are split into two groups: simple and multiple.
Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
C.budget for fixed expenses before flexiable expenses
