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Alex_Xolod [135]
3 years ago
5

Dell Corporation sent five different versions of their email to customers to determine which message was most effective at getti

ng customers to make online purchases. While online sales rose by nearly 20%, two of the versions demonstrated higher than normal click-through rates. Such experimentation done in a realistic environment would be called a
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Field Experiment

Step-by-step explanation:

According to my research on different types of experimentation methods, I can say that based on the information provided within the question this would be called a Field Experiment. This is a type of experiment that is done in the daily lives of the subjects and their environment, and the researcher has no control over the variables surrounding the experiment. This situation can be called a field experiment since the company is sending the emails to potential customers who will view it during their everyday life/routine and the company has no control over any other variables other than the email.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Any help with an explanation would be appreciated!
Lilit [14]

Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)

h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
5 0
3 years ago
The width of the figure below is 5 units. The perimeter of the figure is 18 units. What is the length of the figure in units?
Talja [164]
The perimeter is all sides length added together. You can make an equation:5+5+x+x where x is the length.
5+5=10    18-10=8     There is two sides so you do eight divided by two
The length is 4

4 0
3 years ago
Read 2 more answers
Consider the following equation
ser-zykov [4K]

Answer:

The perpendicular line is:

y = 1/3  x + 2/3

Step-by-step explanation:

The given equation can be reduced to its slope-intercept form as shown below:

3x + 9y = 8y - 2

subtract 8 y from both sides

3 x + y = -2

subtract 3 x from both sides

y = - 3 x -2

therefore we know that the slope of this line is -3, and then, a perpendicular line to it must have slope given by the "opposite of the reciprocal" of this slope. That is, the slope of any perpendicular line to this one must be: 1/3

We use this slope to find the equation of the line passing through the point (13. 5)

y = 1/3 x + b

passing through (13, 5) means:

5 = 1/3 (13) + b

therefore, we can find b from the above equation

b = 5 - 13/3 = 15/3 - 13/3 = 2/3

Then the equation of this perpendicular line is:

y = 1/3  x + 2/3

6 0
3 years ago
Take a look at the pictures. The first one has the map and question. The second one has the possible answers.
LenaWriter [7]
The Answer Is B And C.
6 0
3 years ago
Check wether the given value is the solution to the equation<br><br> 3(y+8)=2y-6 y=30
erma4kov [3.2K]
30+8*3=114 2y-6=56.... I think your answer would be 170 but I'm not completely sure
4 0
4 years ago
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