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attashe74 [19]
4 years ago
6

An image point has coordinates B'(7, -4). Find the coordinates of its pre-image if the translation used was (x + 4, y + 5).

Mathematics
2 answers:
Anna11 [10]4 years ago
8 0

Answer:

The coordinate of pre-image is, B(3 , -9).

Step-by-step explanation:

Given an image point has coordinate B'(7, -4).

We have to find the coordinates of its pre-image:

The rule of translation on pre-image (x, y) is given by;

B(x, y) \rightarrow B'(x + 4, y + 5)

then;

(7, -4) = (x+4, y+5)

on comparison we have;

x+4 = 7 and y + 5 = -4

First solve for x;

x + 4 = 7

Subtract 4 from both sides we have;

x + 4 -4 =7-4

Simplify:

x = 3

To solve for y;

y+5 = -4

Subtract 5 from both sides we get;

y = -9

Therefore, the coordinate of pre-image is, B(3, -9)

Olenka [21]4 years ago
6 0

Answer:

The coordinate of pre-image is, B(3 , -9).

Step-by-step explanation:

Given an image point has coordinate B'(7, -4).

We have to find the coordinates of its pre-image:

The rule of translation on pre-image (x, y) is given by;

then;

(7, -4) = (x+4, y+5)

on comparison we have;

x+4 = 7 and y + 5 = -4

First solve for x;

Subtract 4 from both sides we have;

x + 4 -4 =7-4

Simplify:

x = 3

To solve for y;

y+5 = -4

Subtract 5 from both sides we get;

y = -9

Therefore, the coordinate of pre-image is, B(3, -9)

Read more on Brainly.com - brainly.com/question/11847183#readmore

Step-by-step explanation:

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Now that we know the slope we can find the equation of the function by using point-slope for of the function which look like this.....

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The 13-foot string is arranged into a rectangle. Let L denote the length of the rectangle,
soldi70 [24.7K]

The expressions for the width, W, and area, A, of the rectangle in terms of L are:

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  • A = \frac{13L - L^{2} }{2}

The expression for the perimeter of a rectangle is given as:

P = 2(L + W)

where L is its length and W its width

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divide through by 2

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So that;

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The required formula for the width as a function of L is: W = \frac{13}{2} - L

b. Area of a rectangle can be expressed as;

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substitute the expression for width in that of area to have

A = L * ( \frac{13}{2} - L)

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A = \frac{13L - L^{2} }{2}

The expression for the area A is: A = \frac{13L - L^{2} }{2}

Visit: brainly.com/question/10452031

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