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attashe74 [19]
3 years ago
6

An image point has coordinates B'(7, -4). Find the coordinates of its pre-image if the translation used was (x + 4, y + 5).

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

The coordinate of pre-image is, B(3 , -9).

Step-by-step explanation:

Given an image point has coordinate B'(7, -4).

We have to find the coordinates of its pre-image:

The rule of translation on pre-image (x, y) is given by;

B(x, y) \rightarrow B'(x + 4, y + 5)

then;

(7, -4) = (x+4, y+5)

on comparison we have;

x+4 = 7 and y + 5 = -4

First solve for x;

x + 4 = 7

Subtract 4 from both sides we have;

x + 4 -4 =7-4

Simplify:

x = 3

To solve for y;

y+5 = -4

Subtract 5 from both sides we get;

y = -9

Therefore, the coordinate of pre-image is, B(3, -9)

Olenka [21]3 years ago
6 0

Answer:

The coordinate of pre-image is, B(3 , -9).

Step-by-step explanation:

Given an image point has coordinate B'(7, -4).

We have to find the coordinates of its pre-image:

The rule of translation on pre-image (x, y) is given by;

then;

(7, -4) = (x+4, y+5)

on comparison we have;

x+4 = 7 and y + 5 = -4

First solve for x;

Subtract 4 from both sides we have;

x + 4 -4 =7-4

Simplify:

x = 3

To solve for y;

y+5 = -4

Subtract 5 from both sides we get;

y = -9

Therefore, the coordinate of pre-image is, B(3, -9)

Read more on Brainly.com - brainly.com/question/11847183#readmore

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The first step in solving any math problem is to read and understand what is given and what is asked.

<h3>Given</h3>

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<em>Additional comment</em>

A graphical solution is attached.

Either equation can be solved for y, and that expression substituted into the other. Solving the first equation for y gives ...

  y = 7 -x

Substituting that into the second equation, we have ...

  3x +(7 -x) = 15

  2x = 8 . . . . . . . subtract 7

  x = 4 . . . . . . divide by 2

  y = 7-4 = 3

(x, y) = (4, 3) is the solution.

We have shown 3 methods of solving the given system of equations. There are other methods that can be used, too, including matrix methods and methods that make use of arrays of the coefficients.

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Step-by-step explanation:

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