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meriva
3 years ago
5

What is the Inverse function of f(x)= x^2 - 49

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0
Answer: the opposite
tatyana61 [14]3 years ago
4 0

Answer:

the opposite

Step-by-step explanation:

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1st person: 13-4/13 9/13
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3 years ago
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Write an expression to represent the perimeter of the figure below. rectangle with 2x-3 and x+2
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Hi there! 

The perimeter is when you add all the sides of a shape. In a rectangle, two sides are the same, and so are the other two. So, if the two sides are 2x-3 and x+2 the expression will be: 

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4 0
3 years ago
The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.
Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0
3 years ago
Which object covers less area?
baherus [9]
Object A. You can use the area theorem to solve. Just do base x height to get the area of a shape.
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2 years ago
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