Answer:
Sir Isaac Newton revolutionised science when he published his argument
Given :
On a coordinate plane,a curved line with 3 arcs, lab led f of x, crosses the x-axis at (negative 2,0), (negative 1,0), (1,0), and (3,0) and the y axis at (0, negative 6).
To find:
f when x = 0. i.e. f (0).
Solution:
since the graph has 3 arcs and 4 solutions, it can be visualized as the follows:
Between each solution, the function has to increase and decrease giving arcs in between.
1. One of the arcs is between (negative 2,0) and negative (1,0)
2. Second arc is between (negative 1,0) and (1,0)
-this arc cuts the y axis, since x= 0 lies between x= -1 & x=1-
3. Third arc is between (1,0) and (3,0)
Therefore only the 2nd arc cuts the y axis
It’s given that the curve cuts the y axis at (0, -6)
That is when x= 0, f(0) =-6
Therefore the value of f (0) is -6 only.
HOPED THIS HELPED LUV!!
Answer:
Here is the summary:
- y = 13x+5 satisfies the points (0, 5) and (-2, -21)
- y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
- y = x-10 satisfies the points (8, -2)
Step-by-step explanation:
Given the equation
The points which satisfy the equation y=13x+5
y = 13x+5
Checking the point (0, 5)
5 = 13(0)+5
5 = 0 + 5
5 = 5
TRUE
Checking the point (-2, -21)
-21 = 13(-2)+5
-21 = -26 + 5
-21 = -21
TRUE
The points which satisfy the equation y=-3x
y = -3x
Checking the point (0, 0)
0 = -3(0)
0 = 0
TRUE
Checking the point (-5, -15)
y = -3x
-15 = -3(-5)
-15 = -15
TRUE
Checking the point (-3, 9)
y = -3x
9 = -3(-3)
9 = 9
TRUE
The points which satisfy the equation y=x-10
y = x-10
Checking (8, -2)
-2 = 8 - 10
-2 = -2
TRUE
Therefore, from the above calculations we conclude the summary:
Here is the summary:
- y = 13x+5 satisfies the points (0, 5) and (-2, -21)
- y = -3x satisfies the points (0, 0), (-5, -15) and (-3, 9)
- y = x-10 satisfies the points (8, -2)
Answer:
3
Step-by-step explanation:
The circle gets bigger, so the only option is a positive whole number.
Answer:
the face would be unrolled and the base (circle) would be at the bottom
it would look like:
