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scoray [572]
3 years ago
5

Which statement about the ordered pairs (-9, 3) and (2, - 4) is true for the equation 6.0 6x - 142 2 9. 3) is a solution to the

equation. (2. 4) is a solution to the equation. O Neither ordered pair is a solution. Both ordered pairs are solutions. 1 2​
Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

It should be Neither ordered pair is a solution

Step-by-step explanation:

I take the same math lol

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Can anyone help me with this problem. This question is a little hard. Is anyone on to help. Can’t understand
exis [7]

Answer: It should be D if im looking at this correctly

Step-by-step explanation:

Plain and simple

7 0
1 year ago
Read 2 more answers
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
Write the function in vertex form, and identify its vertex. g(x) = 5x2 - 50x + 128
steposvetlana [31]
Hello : 
<span>g(x) = 5x² - 50x + 128    
       = 5(x²-10x +128/5)
       = 5 (x²-10x+5²-5² +128/5)
        = 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
3 0
3 years ago
What is the equation of the line that passes through the point (6,3) has a slope of -1/3
DerKrebs [107]

Answer:

y = -1/3x + 5

Step-by-step explanation:

y = mx + b

so y = 3, x = 6, m = -1/3

then 3 = (-1/3)6 + b

3 = -2 + b

b = 5

so y = -1/3x + 5

5 0
2 years ago
Pls help!!!!Shawn used 15 centimeters of tape to wrap 5 presents . How much tape will Shawn need I all if he has to wrap 13 pres
Ilia_Sergeevich [38]

Answer:39

Step-by-step explanation:

15÷5=3

3×13=39

3 0
3 years ago
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