Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
The final solution is y=-5/3x-10
Answer:C 5a^2 +70a +240
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
The equation of 2 quantities in direct proportion is
y = kx ← k is the constant of proportionality
1
y = - 4x ← in standard form
with k = - 4
2
= 2 ( multiply both sides by x )
y = 2x ← in standard form
with k = 2
3
= 3 ( multiply both sides by y )
x = 3y ( divide both sides by 3 )
x = y ← in standard form
with k =
