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borishaifa [10]
3 years ago
14

The weight V of an object on Venus varies directly with its weight E on Earth. A person weighing 120 lb on Earth would weigh 106

lb on Venus. How much would a person weighing 150 lb on Earth weigh on Venus?
Mathematics
2 answers:
sukhopar [10]3 years ago
5 0
We have
120lbs Earth................................106lbs Venus
150lbs Earth...................................?Venus

Venus weight=150*106/120=132.50 lbs
svlad2 [7]3 years ago
4 0

Answer:

The person weighing 150 lb on Earth will weight 132.5 lb on Venus.

Step-by-step explanation:

The weight of object on Venus varies directly with its weight on the Earth.

w_v\propto w_e..(1)

\frac{w_v}{w_e}=k=constant

w_v= Weight on Venus

w_e= Weight on Earth

If the weight of person on Earth =w_e=120 lb

If the weight of that person on Venus=w_v=106 lb

And,the weight of another person on Earth =w_e'=150 lb

The weight of another person on Venus=w_v'=?

\frac{w_v}{w_e}=\frac{w_v'}{w_e'} (From 1)

w_v'=\frac{w_v\times w_e'}{w_e}=\frac{106 lb\times 150 lb}{120 lb}

w_v'=132.5 lb

The person weighing 150 lb on Earth will weight 132.5 lb on Venus.

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Answer:

C because if you make $17 dollars an hour that's 2,080 hours a year, Multiply that and you got C

6 0
3 years ago
The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

5 0
3 years ago
Sean bought a laptop and a printer.
stealth61 [152]

Answer:

£102.04

Step-by-step explanation:

£1250 - £1100 = £150

printer sold for £150

£150 = 147%

1% = 1.0204

100% = 102.0408

to 2dp = £102.04

3 0
2 years ago
In circle O, m∠R = 30.8°. Find m∠NOQ.
nordsb [41]

Given:

In circle O, m∠R = 30.8°.

To find:

The m∠NOQ

Solution:

Central angle theorem: According to this theorem, the central angle is always twice of subtended angle on the same arc.

Angle NOQ and angle NRQ are on the same arc but ∠NOQ is the central angle and ∠NRQ is the subtended angle on the arc NQ.

Using central angle theorem, we get

m\angle NOQ=2\times m\angle NRQ

m\angle NOQ=2\times m\angle R

m\angle NOQ=2\times 30.8^\circ

m\angle NOQ=61.6^\circ

Therefore, m\angle NOQ=61.6^\circ.

4 0
3 years ago
Solve x2-4x-7=0 by completing the square ​
aleksklad [387]
HEY mate here is pratyush from India for your help...

the answer is with the attachment

hope it helps you..

8 0
3 years ago
Read 2 more answers
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