What is 350-450:90+15x3

If a person flips a coin and then rolls a six dash sided die, describe the sample space of possible outcomes using Upper H comm

xenn [34]

Answer:

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }

Step-by-step explanation:

If a person flips a coin; the possible outcomes of flipping a coin are { Head (H), Tail (T) }

If a person rolls a six dash side die, the possible outcomes of rolling a dice are { 1, 2, 3, 4, 5, 6 }

Now, If a person flips a coin and then rolls a six dash side die;

The Sample Space (S) which is the set of all the possible outcomes of the activities carried out can be described as follows:

DIE COIN →

↓

H T

1 (1,H) (1,T)

2 (2,H) (2,T)

3 (3,H) (3,T)

4 (4,H) (4,T)

5 (5,H) (5,T)

6 (6,H) (6,T)

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }

3 0

3 years ago

What is the equivalent fraction for 24/0.64?

mestny [16]

Answer:

See below

Step-by-step explanation:

24/ .64 = 2400 / 64 = 37 1/2 = 75/2

4 0

1 year ago

Read 2 more answers

A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found

irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

$H_0: p = 0.04$

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

$H_a: p > 0.04$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that $\mu = 0.04, \sigma = \sqrt{0.04*0.96}$

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that $n = 20, X = 0.1$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}$

$z = 1.37$

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0

2 years ago

Read 2 more answers

delilah studies the wolf population of a nearby national park. She has calculated that the population decreased by 1.25% per yea

KATRIN_1 [288]

Step-by-step explanation:

i need time

i hope u may understand

8 0

3 years ago

Read 2 more answers

Classify by degree and number of terms, in that order<br><br> 5x^2-2x+3

zmey [24]

Answer:

no tiene respuesta perdon

6 0

2 years ago