Answer:
806 yd sq.
Step-by-step explanation:
Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.
They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.
You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.
The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.
Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.
Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.
Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.
The surface area would be 806 yd sq.
40°, 60° and 80°
sum the parts of the ratio 2 + 3 + 4 = 9
The sum of the angles in a triangle = 180°
Divide 180 by 9 to find one part of the ratio
= 20° ← 1 part of the ratio
2 parts = 2 × 20 = 40°
3 parts = 3 × 20 = 60°
4 parts = 4 × 20 = 80°
The angles in the triangle are 40°, 60° and 80°
The amount of space left with the snakd container inside the wastebasket=
=(volume of the wastebasket) - (volume of the sanak container)
Volume (cylinder)=area of the circle * height
1) We calculate the volume of a wastebasket:
area of the circle=πr²=π(5 in)²=25π in²
heigth=20 in.
Volume=25π in² * 20 in=500π in³.
2) we calculate the volume of the snack container:
area of the circle=πr²=π(4 in)²=16π in²
heigth=6 in.
Volume=16π in² * 6 in=96π in³
3) we calculate the amount of space left with the sanak container inside the wastebasket.
amount of space left=500π in³ - 96π in³=404π in³
404π in³=404 * 3.141592654...in³≈1269.2 in³
Answer: 404π in³ or ≈1269.2 in³
Answer:
7) x= 5, 8) x= 6, 9) x= 7
Step-by-step explanation:
As per the secant theoram, if two secant intersect outside the circle then the product of the exterior secant and total length of each secant are equal.
7) ∴ 
opening parethesis and distributing 3 with x and 3.
⇒ 
subtracting 9 on both side.
⇒ 
cross multiplying
∴ x= 5.
8) 
Opening parethesis and distributing 4 with x and 4.
⇒ 
⇒ 
subtracting 16 on both side.
⇒ 
cross multiplying
∴ x= 6.
9) 
opening parethesis and distributing 5 with x and 5.
⇒ 
subtracting 25 on both side.
⇒ 
cross multiplying
∴ x= 7.
