Find the average distance each data value in the set is from the mean. Round
1 answer:
You might be interested in
Answer with explanation:
Alison is learning how to walk.50% of times she takes a step she falls down.
Probability of falling down in next step
Probability of not falling down in next step
From ,the four option given,we have to find the best simulation which her older brother wants to design a simulation to find the probability that she will fall down 5 out of the next 7 times she tries to take step.
While Simulating the Probability of falling down should be
And , probability of not falling down
→→⇒F=Falling, NF=Non Falling
A) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die five times.
Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.
B) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die seven times.
Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.
C) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin five times.
Simulation is done only five times , that is coin has been flipped only five times.it must have been flipped seven times.Incorrect option.
D) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin seven times.
Simulation is done seven times , that is coin has been flipped seven times.So,she should fall 5 times that is head should appear 5 out of seven times, and tail should appear 2 out of seven times.correct option.
Option D
Answer:
a) 0.0256 = 2.56% probability of 4 heads.
0.1296 = 12.96% probability of 4 tails.
b) The probability is 0.0576 = 5.76%.
c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses
Step-by-step explanation:
For each throw, we have these following probabilities:
0.4 = 40% probability of heads.
0.6 = 60% probability of tails.
(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.
4 heads:
4 throws, each with 0.4 probability of heads. So
0.0256 = 2.56% probability of 4 heads.
4 tails:
4 throws, each with 0.6 probability of tails. So
0.1296 = 12.96% probability of 4 tails.
(b) Determine the probability of H T H T in 4 tosses.
H = 0.4, T = 0.6. So
The probability is 0.0576 = 5.76%.
(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)
Number of outcomes:
The possible outcomes are:
H - H - T - T
H - T - H - T
H - T - T - H
T - H - H - T
T - H - T - H
T - T - H - H
6 outcomes given 2 heads in 4 tosses.
Each with probability 0.0576, as found in b)
6*0.0576 = 0.3456
0.3456 = 34.56% probability of 2 heads in 4 tosses