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3 years ago

What two numbers have a sum of 215 and a difference of 137

Mathematics

1 answer:

BabaBlast [244]3 years ago

3 0

Answer:

see below

Step-by-step explanation:

let x = big number

let you = small number

x + y = 215-------> (1)

x - y = 137 ------>(2)

(1)

x = 215 - y ----->(1)

substitute 1 into 2

215 - y -y = 137

-2 y = 78

y = 39

substitute y = 39 into (1)

x = 215 - (39)

x = 176

thus the numbers are 176 & 39

hope this helps

please mark it brainliest

it took me quite long to do this

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2 years ago

Sin theta = 9/15. Find tan theta. A. 15/12. B. 9/12 C. 12/15 D. 12/9

Finger [1]

Answer:

Step-by-step explanation:

$Sin \ theta = \frac{9}{15}=\frac{Opposite \ side}{hypotenuse}\\$

Pythagorean theorem,

Adjacent side ² = hypotenuse² - opposite side²

= 15² - 9²

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Adjacent side = √144 = √(12*12) = 12

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3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

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Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

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3 years ago

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almond37 [142]

Answer:

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3 years ago

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egoroff_w [7]

Answer:

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3 years ago